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4a^2-8a-140=0
a = 4; b = -8; c = -140;
Δ = b2-4ac
Δ = -82-4·4·(-140)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-48}{2*4}=\frac{-40}{8} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+48}{2*4}=\frac{56}{8} =7 $
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